`Tìm` `x,y` `biết` `:` `a)` $(2x - 1)^{10}$ `=` $49^{5}$ `b)` $dfrac{1+3y}{12}$ `=` $dfrac{1+ 5y}{5x}$ = $dfrac{1+7y}{4x}$

`Tìm` `x,y` `biết` `:` `a)` $(2x - 1)^{10}$ `=` $49^{5}$ `b)` $\dfrac{1+3y}{12}$ `=` $\dfrac{1+ 5y}{5x}$ = $\dfrac{1+7y}{4x}$
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