a, $frac{x+3}{x²-1}$+$frac{3}{x-1}$=$frac{2}{x+1}$ b, $frac{x-5}{x²-1}$+$frac{3}{x+1}$=$frac{2}{x-1}$ c, $frac{2x+1}{x²-4}$+ $frac{3}{x+2}$=$frac{2}{x-2}$ Giải pt

2025-03-06 01:37:03

a, $\frac{x+3}{x²-1}$+$\frac{3}{x-1}$=$\frac{2}{x+1}$ b, $\frac{x-5}{x²-1}$+$\frac{3}{x+1}$=$\frac{2}{x-1}$ c, $\frac{2x+1}{x²-4}$+ $\frac{3}{x+2}$=$\frac{2}{x-2}$ Giải pt

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